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Save on Textbooks! Other   Other Homework Help ( 1213 ) Math   Math- Algebra 1 ( 2437 )   Math- Algebra 2 ( 1189 )   Math- Calculus ( 381 )   Math- Geometry ( 594 )   Math- Other ( 1522 )   Math- Precalculus ( 408 )   Math- Trigonometry ( 285 ) Biology   Biology- Animal ( 155 )   Biology- Cell ( 530 )   Biology- Ecological ( 109 )   Biology- General ( 651 )   Biology- Microbiology ( 100 ) Business   Business- Accounting ( 674 )   Business- Finance ( 511 )   Business- Other ( 454 ) Chemistry   Chemistry- Biochem ( 162 )   Chemistry- Organic ( 166 )   Chemistry- Other ( 1330 ) Economics   Economics- Macroeconomics ( 829 )   Economics- Microeconomics ( 610 ) Essay Service   Essay Correction ( 96 )   Essay Writing ( 396 ) History   History- World ( 831 )   US History- Post 1877 ( 472 )   US History- Pre 1877 ( 347 ) Language   English ( 829 )   Foreign Languages ( 118 )   World Literature ( 196 ) Physics   Physics- Electricity, Magnetism ( 248 )   Physics- General ( 1736 )   Physics- Mechanical, Heat, Sound ( 343 )   Physics- Wave, Quantum Physics ( 114 ) z Medical Questions Your Question Hey there. Hoping someone can help walk me through the steps to answer these 5 questions. They all spin off form the following: Consider a 0.586 M aqueous solution of barium hydroxide- Ba(OH)2 (aq) 1. How many grams Ba(OH)2 are dissolved in 0.191 dL of 0.586 M Ba(OH)2 (aq) 2. How many individual hydroxide ions (OH-1) are found in 13.4 mL of 0.586 M Ba(OH)2 (aq) 3. What volume in L of 0.586 M Ba(OH)2 (aq) contains 0.466 OUNCES of Ba(OH)2 disolved in it? 4. If 16.0 mL of water are added to the 31.5 mL of 0.586 M Ba(OH)2 what is the new solutions molarity? 5. Suppose you had titrated your vinegar sample with barium hydroxide insead of sodium hydroxide: BA(OH)2 (aq) a 2HC2H3O2 (aq)--> Ba(C2H3O2)2 (aq) + 2H2O(l) What volume in mL of 0.586 M Ba(OH)2 (aq) must be added to a 5.00 mL sample of vinegar to reach the equivalence point. You can just use X to represent the Molarity of vinegar. Thanks so much for your help! Please Login to Answer the Question LOGIN

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